7=x(4+3)^2+2

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Solution for 7=x(4+3)^2+2 equation: 



7=x(4+3)^2+2

We move all terms to the left:

7-(x(4+3)^2+2)=0

We add all the numbers together, and all the variables

-(x7^2+2)+7=0

We get rid of parentheses

-x7^2-2+7=0

We add all the numbers together, and all the variables

-x7^2+5=0

We move all terms containing x to the left, all other terms to the right

-x7^2=-5

x=-5/1

x=-5

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